((4-2x)/3)^2=3-x

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Solution for ((4-2x)/3)^2=3-x equation: 


x in (-oo:+oo)

((4-(2*x))/3)^2 = 3-x // - 3-x

((4-(2*x))/3)^2+x-3 = 0

((4-2*x)/3)^2+x-3 = 0

((4-2*x)^2)/(3^2)+x-3 = 0

((4-2*x)^2)/(3^2)+(3^2*x)/(3^2)+(-3*3^2)/(3^2) = 0

(4-2*x)^2+3^2*x-3*3^2 = 0

4*x^2-7*x-27+16 = 0

4*x^2-7*x-11 = 0

4*x^2-7*x-11 = 0

4*x^2-7*x-11 = 0

DELTA = (-7)^2-(-11*4*4)

DELTA = 225

DELTA > 0

x = (225^(1/2)+7)/(2*4) or x = (7-225^(1/2))/(2*4)

x = 11/4 or x = -1

(x+1)*(x-11/4) = 0

((x+1)*(x-11/4))/(3^2) = 0

((x+1)*(x-11/4))/(3^2) = 0 // * 9

(x+1)*(x-11/4) = 0

( x+1 )

x+1 = 0 // - 1

x = -1

( x-11/4 )

x-11/4 = 0 // + 11/4

x = 11/4

x in { -1, 11/4 }

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